Question

determine x in (-2)^5×(-2)^3(-2)^4=(-2)^2x​

Answer 1

(-2)⁵×(-2)³×(-2)⁴= (-2)²ˣ

Since the base is same and powers are different, we add the powers

(-2)⁽⁵⁺³⁺⁴⁾= (-2)²ˣ

(-2)¹²=(-2)²ˣ

Now, again base is same, we solve the powers

12=2x

x= 12/2

x= 6

Thus. the value of x is 6.

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