determine x so that 2 is the slope of the line through P(2,5) and Q(x,3).
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Answered by
57
By using distance formula,
(2) square = (x-2) square+(3-5) square
4 = x^2-4x+4+4
4 = x^2-4x+8
x^2-4x+8-4 = 0
x^2-4x+4 = 0
x^2-2x-2x+4= 0
x(x-2)-2(x-2) = 0
(x-2)(x-2) = 0
x = 2
(2) square = (x-2) square+(3-5) square
4 = x^2-4x+4+4
4 = x^2-4x+8
x^2-4x+8-4 = 0
x^2-4x+4 = 0
x^2-2x-2x+4= 0
x(x-2)-2(x-2) = 0
(x-2)(x-2) = 0
x = 2
sai928:
but we should get answer as 1
how..
my answer is not correct
???
for slope we have to use=y2-y1 by x2-x1
then we get =3-5 by x-2 =2 after this -2=2x-4 next 2x=2 the answer is x=1.
ok is it Clear
Answered by
63
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