Question

Determine x so that 2 is the slope of the line through P(2, 5) and Q(x, 3).

Answer 1

Hi ,

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We know that ,

Slope of a line joining two points

( x1 , y1 ) and ( x2 , y2 ),

m = ( y2 - y1 )/( x2 - x1 )

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Here ,



P( 2 , 5 ) = ( x1 , y 1 ),

Q( x , 3 ) = ( x2 , y2 )

slope ( m ) = 2

( y2 - y1 )/( x2 - x1 ) = 2

( 3 - 5 )/( x - 2 ) = 2

( - 2 ) = 2 ( x - 2 )

( -2 )/2 = x - 2

- 1 = x - 2

- 1 + 2 = x

1 = x

Therefore ,

x = 1

I hope this helps you.

: )

Answer 2

$\text {slope} =\dfrac{Y_2 - Y1}{X_2 - X_1}$

Given that P(2, 5) and Q(x, 3), find slope:

$2 =\dfrac{5-3}{2 -x}$

$2 =\dfrac{2}{2 -x}$

$2(2 - x) = 2$

$4 - 2x = 2$

$2x = 2$

$x = 1$

Answer: The value of x is 1.