Question

Determine x so that x-2, 4x-1, and 5x+2 are the three consecutive terms of an. A. P

Answer 1

please mark it as the brainliest answer

Answer 2

Answer:

$\red { Value \: of \: x } \green {= 1 }$

Step-by-step explanation:

$Given \: (x-2), (4x-1) \:and \: (5x+2) \: are \: the\\three \: consecutive \: terms \:of \:an \:A.P$

$a_{2} - a_{1} = a_{3} - a_{2}$

$( Difference \: of \: consecutive \:terms )$

$\implies 4x-1 - (x-2) = 5x+2 - (4x-1)$

$\implies 4x - 1 - x + 2 = 5x + 2 - 4x + 1$

$\implies 3x + 1 = x + 3$

$\implies 3x - x = 3 - 1$

$\implies 2x = 2$

$\implies x = \frac{2}{2} = 1$

Therefore.,

$\red { Value \: of \: x } \green {= 1 }$

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