Math, asked by shakilfincu11, 9 months ago

Dev can hit a target 3 times in 6 shots Pawan can hit the target 2 times in 6 shots and Lakhan can hit the target 4 times in 4 shots. What is the probability that at least 2 shots hit the target?​

Answers

Answered by callofduty123
15

Answer:

2/3 is the probability that atleast 2 shot hits the target if each takes one short

Step-by-step explanation:

Dev can hit a target 3 times in 6 shots

=> probability of D hitting = (3/6) = 1/2

=> probability of D not hitting = 1/2

Pawan can hit the target 2 times in 6 shots

=> probability of P hitting = (2/6) = 1/3

probability of P not hitting = 2/3

Lakhan can hit the target 4 times in 4 shorts.

=> probability of L hitting = (4/4) = 1

probability of L not hitting = 0

Now if Dev , Pawan & Lakhan Each hit a short

Chances that atleast 2 shorts hit the target

= DP(not L) + DL(notP) + LP(notD) + DPL

= (1/2)(1/3)(0) + (1/2)(1)(2/3) + (1)(1/3)(1/2) + (1/2)(1/3)(1)

= 0 + 1/3 + 1/6 + 1/6

= 0 + 1/3 + 1/3

= 2/3

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