Dev can hit a target 3 times in 6 shots Pawan can hit the target 2 times in 6 shots and Lakhan can hit the target 4 times in 4 shots. What is the probability that at least 2 shots hit the target?
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Answer:
2/3 is the probability that atleast 2 shot hits the target if each takes one short
Step-by-step explanation:
Dev can hit a target 3 times in 6 shots
=> probability of D hitting = (3/6) = 1/2
=> probability of D not hitting = 1/2
Pawan can hit the target 2 times in 6 shots
=> probability of P hitting = (2/6) = 1/3
probability of P not hitting = 2/3
Lakhan can hit the target 4 times in 4 shorts.
=> probability of L hitting = (4/4) = 1
probability of L not hitting = 0
Now if Dev , Pawan & Lakhan Each hit a short
Chances that atleast 2 shorts hit the target
= DP(not L) + DL(notP) + LP(notD) + DPL
= (1/2)(1/3)(0) + (1/2)(1)(2/3) + (1)(1/3)(1/2) + (1/2)(1/3)(1)
= 0 + 1/3 + 1/6 + 1/6
= 0 + 1/3 + 1/3
= 2/3
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