devansh,saransh,and shashank have apples with them. Saransh has y apples and devansh has 9 more apples then saransh and shashank has 8 less apples than saransh. Find the number of apples with shashank and saransh and also find the total number of apples all have
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Answer:
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Step-by-step explanation:
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Answer:
No. of apples with Saransh = y
No. of apples with Shashank = y-8
Total no. of apples = x-1/3
Step-by-step explanation:
(Let the total no. of apples be x)
No. of apples Saransh has = y
No. of apples Devansh has = y+9
No. of apples Shashank has = y-8
BTQ
=> y + (y+9) + (y-8) = x
=> 3y+1 = x
=> 3y = x-1
=> y = x-1/3
∴ No. of apples with Saransh = y
No. of apples with Shashank = y-8
Total no. of apples = x-1/3
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