Question

Develop a short paragraph showing the results of the S.S.C. Exam of March 2013 of Nagpur division. The pie-chart shows the passing percentage. Compare and contrast the information and write a paragraph. 1) Wardha 27.83% 2)Gadchiroli 30.94% 3)Bhandara - 27.83% 4)Nagpur - 34.39% 5)Chandrapur - 32.09%​

Answer 1

Answer:

Let the breadth of the rectangle be x cm.

Then, the length of the rectangle is (x+9) cm.

So, area of rectangle = length x breadth =x(x+9)cm

2

Now, length of new rectangle =(x+9+3) cm =(x+12) cm and

breadth of new rectangle =(x+3) cm.

So, area of new rectangle = length × breadth =(x+12)(x+3)cm

2

According to the given condition,

(x+12)(x+3)=x(x+9)+84

⇒x

2

+12x+3x+36=x

2

+9x+84

⇒15x+36=9x+84

⇒15x−9x=84−36

⇒6x=48

⇒x=8

So, breadth of the rectangle is 8 cm and length

=8+9=17 cm.

Answer 2

Answer:

contrast the information and write a paragraph. 1) Wardha 27.83% 2)Gadchiroli 30.94% 3)Bhandara - 27.83% 4)Nagpur - 34.39% 5)