Devender bought some apples at rate of rs 5 per apple. He also bought an equal number of bananas at rate of rs 2 per banana. He sold the apples at the profit of 20% and the bananas at the loss of 5%,but still made an overall profit of rs360 after selling all the fruits. What is the number of apples he had purchased?
Answers
Answer:
He had purchased x = 87.80 number of apples.
Step-by-step explanation:
Let the no. of apples bought be x
Cost of one apple = ₹ 5
Therefore, cost of x apples = ₹ 5x
Profit = 20%
Therefore, S.P. = (1+p/100) C.P.
= (1+20/100) C.P.
= (1+1/5) C.P.
= 6/5 × 5x = 6x
Again,
Since, the number of bananas is equal to the number of apples
Therefore, no. of bananas = x
Cost of one banana = ₹ 2
Therefore, cost of x bananas = ₹ 2x
Loss = 5%
Therefore, S.P. = (1-l/100) C.P.
= (1-5/100) C.P.
= (1-1/20) C.P.
= 19/20 × 2x = 19x/10
Overall profit = ₹ 360
Therefore, 6x-19x/10 = 360
Or, 60x-19x/10 = 360
Or, 41x/10 = 360
Or, x = 3600/41 = 87.80.(answer).
PLEASE SELECT MY ANSWER AS THE BRAINLIEST ANSWER.
Answer=
he purchased 87.80 apples.
Step-by-step explanation:
Let the apple be x
and banana be y
Cost price of all apples =5x
Cost price of all bananas = 2x
Profit on apples is 20%
Loss on bananas is 5%
Selling price of apples = (1+p/100)CP
=( 1+20/100) 5x
=(1+1/5)5x
=6/5*5/x
=6x
Selling price of bananas= (1-l/100)CP
=(1-5/100)2x
=(1-1/20)2x
=(19/20)2x
=19x/10
According to the problem, Overall profit is Rs 360.
then SP of apples -SP of bananas=Rs 360
6x-19x/10 =360
(60x-19x)÷10 =360
41x =3600
x=3600÷41
x =87.80
that means he purchased 87.80 apples.