If one root of the equation 2X square +kx+4=0 is 2 then other root is what
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Answered by
5
Answer:
k = -6 and root = 1
Step-by-step explanation:
let another root be A.
Then,
2 + A = -k/2(I)
and 2.A = 4/2...(II)
from II we have A = 1
and substituting it in (I)
we get k = -6.
Answered by
3
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Step-by-step explanation:
given,
2x^2+kx+4=0
and one of the root = 2
another root = ?
2x^2+kx+4=0
2x(x-2)-2(x-2)=0
(2x-2)(x-2)=0
2x= 2 x=2
x = 1
therefore another root=1
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