Deveshi has a total of ₹590 as currency notes in the denominations of ₹50 , ₹20 and ₹10. The ratio of the number of ₹50 notes and ₹20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?
Answers
Solution :
Let the number of ₹50 notes and ₹20 notes be 3x and 5x, respectively
But she has 25 notes in total.
Therefore, the number of ₹10 notes
➸ 25 - (3x + 5x)
➸ 25 - 8x
The amount she has
from ₹50 notes: 3x x 50 = ₹150x
from ₹20 notes: 5x x 20 = ₹100x
from ₹10 notes: (25 - 8x) x 10 = ₹(250 - 80x)
Hence the total money she has =150x + 100x + (250 - 80x)
➸ ₹(170x +250)
now, 170x + 250 = 590
or 170x = 590 - 250 = 340
➸ x = 340/170
➸ x = 2
The number of ₹50 notes she has
➸ 3x
➸ 3 x 2
➸ 6
The number of ₹20 notes she has
➸ 5x
➸ 5 x 2
➸ 10
The number of ₹10 notes she has
➸ 25 - 8x
➸ 25 - (8 x 2)
➸ 25 - 16
➸ 9
____________________
_________
Given :-
_________
Devshi has 590 Rupees
RS50,20&10 are there ⇒ Total 25 notes.
_________
SOLUTION:-
_________
Rs50&Rs20 ⇒3:5
Notes of Rs50=3x
Notes of Rs20=5x
Notes of Rs10=25−(3x+5x)=25−8x.
Amount in 50 Rupee notes ⇒50×3x=150x
Amount in 20 Rupee notes ⇒20×5x=100x.
Amount in 10 Rupee notes ⇒10(25−8x)=250−80x
Total Amount =590
⇒150x+100x+250−80x=590
⇒250−80x=590−250
⇒170x=340
∴x=2
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So Deveshi has:-
Notes of Rs.50=3(2)=6i.e;150(2)=300Rs.
Notes of Rs.20=5(2)=10i.e;100(2)=200Rs.
Notes of Rs.10=25−8(2)=9i.e;=90Rs