Question

Deveshi has a total of ₹590 as currency notes in the denominations of ₹50 , ₹20 and ₹10. The ratio of the number of ₹50 notes and ₹20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?​

Answer 1

Hi,

Since Rs 50 & Rs 20 are in the ratio we can write,

No. of Rs 50 notes = 3x

No. of Rs 20 notes = 5x

As She has a total of 25 notes, 

So, we can write,

No. of Rs 10 notes = 25-(3x+5x) = 25-8x

Now we calculate the actual amount of each notes,

Rs 50 note amount to = Rs 50×3x = Rs 150x

Rs 20 note amount to = Rs 20×5x = Rs 100x

Rs 10 note amount to = Rs [10×(25-8x)] = Rs [250-80x]

Total sum of money he has = Rs 590

According to the problem,

150x + 100x + 250 - 80x = 590

170x = 340

x = 2

Now we find out the actual number of notes as,

No. of Rs 50 notes = 3 × 2 = 6 ;

No. of Rs 20 notes = 5 × 2 = 10 ;

No.of Rs 10 notes = 25-(8 × 2) = 9

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Answer 2

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Deveshi has a total of ₹590 as currency notes in the denominations of ₹50 , ₹20 and ₹10. The ratio of the number of ₹50 notes and ₹20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?

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Let,

The number of ₹50 notes and ₹20 notes be 3x and 5x, respectively.

But she has 25 notes in total.

Therefore, the number of 10 notes = 25 - ( 3x + 5x ) = 25 - 8x

The amount she has

from ₹50 notes: 3x × 50 = Rs 150x

from ₹20 notes: 5x × 20 = Rs 100x

from ₹10 notes: ( 25 - 8x ) × 10 = Rs ( 250 - 80x )

Hence, the total money she has = 150x + 100x + ( 250 - 80x ) = Rs ( 170x + 250 )

But she has Rs 590.

Therefore, 170x + 250 = 590

170x = 590 - 250

170x = 340

x = 340/170

x = 2

The number of ₹50 notes she has = 3x

= 3 × 2 = 6

The number of ₹20 notes she has = 5x

= 5 × 2 = 10

The number of ₹10 notes she has = 25 - 8x

= 25 - ( 8 × 2 )

= 25 - 16 = 9