Math, asked by kripananma20, 1 month ago

Devi’s mother is three times as old as Devi. Five years ago, Devi’s mother was four times
as old as Devi was then. Find their present ages


Please do answer step by step in paper ​

Answers

Answered by sg3333088
2

Answer:

15 and 45

Step-by-step explanation:

Let present ages of Devi = x

her mother = 3x

5 years ago age

of Devi = x-5

her mother = 3x-5

4 times the age of Devi.

4(x-5) = 3x-5

4x-20 = 3x-5

or 4x-3x = -5+20

x= 15

Present ages of Devi is 15

Present age of Devi's mother is 45.

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Answered by beulab2006
1

Answer:

✰✰|| Given ||✰✰

Devi’s mother is three times as old as Devi.

Five years ago, Devi’s mother was four times as old as Devi

✰✰|| To Find || ✰✰

Present age of Devi's mother

✪|| Solution ||✪

Let, the devi age be x

age of Devi's mother = 3x

age of Devi's mother 5 years ago = 4x

⇒ 3x - 5 years = 4x - 20 years

⇒ 20 - 5 years = 4x - 3x

⇒ 15 years = x

present age of Devi's mother = 3x

⇒ present age of Devi's mother = 3 × 15 years

⇒ present age of Devi's mother = 45 years

present age of Devi's mother is 45 years

Step-by-step explanation:

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