devide :( x³+x³‐17x+15)÷(x‐1)
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Step-by-step explanation:
it cant as exponential graph wont mare a parabola which touches x axis
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Answer:
Solution
Let x-3=0
⇒x=3
Let p(x)=x3+x2−17x+15
⇒p(3)=33+32−17(3)+15=27+9−51+15=0
∵ The remainder is zero when putting x=3.
∴ x-3 is a factor of given polynomial.
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