Math, asked by aliyachana169, 10 months ago

Dhwani age at present is 2 year less then 6 times the age of here soon amar.the product of their ages 5 years later will be 33/. what was the age of dhwani when her son Amar was born

Answers

Answered by GulabLachman
2

Dhwani age at present is 2 year less then 6 times the age of here soon amar.the product of their ages 5 years later will be 330.Age of dhwani was 23 years old when her son Amar was born

Let us consider the present age of Dhwani be 'x' years and her son Amar be 'y' years.

Given that, Dhwani’s present age is 2 years less than 6 times her son Amar. We represent the above statement in equation as:

x = 6y – 2  ..(1)

After 5 years:

Amar’s age = (y + 5)  years

Dhwani’ age = (x + 5) years

Replacing the value of x from (1),

Age = (6y – 2 + 5)

= (6y + 3) years  

Again, it is given that tthe product of their ages is 330.

So,

[(y+5)*(6y+3)] = 330

⇒ 6y² + 3y + 30y + 15 = 330

⇒ 6y² + 33y – 315 = 0

⇒ 2y² + 11y – 105 = 0                    [dividing by 3 on both sides]

⇒ 2y² + 21y – 10y – 105 = 0

⇒ 2y(y+10.5) – 10(y+10.5) = 0

⇒ (y+10.5)(2y-10) = 0

By zero product's rule,  we get

y = 10/2 = 5, as age cannot be negative.

x = 6y + 3 according to eqn.(1).

x = 6(5) + 3 = 30 + 3

= 33years

So, when Amar was born Dhwani was (28-5) = 23 years old.

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