Diagonal AC and BC of a Trapezium ABCD with Ab parallel DC each other at the point O. using a similarity Criterion for two Triangles show that OA /OB =OB/OD
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How it is possible.OA/OB=OB/OD
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from 1 and 2 ao/bo =co/do
made correction in question that ao/bo=co/do
hope this will help u
made correction in question that ao/bo=co/do
hope this will help u
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