Diagonal ac and bd of abcd aiesec rac ocr a p. Sow a ar(apb)*ar(cpd)=ar(apd)*ar(bpc)
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Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that ar ( APB) x ar (CPD) = ar (APD) x ar (BPC).
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Answer:
Step-by-step explanation:
A
RA DCBA
ADBA ABDA
ABCD AR
A
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