Question

Four years ago, the age of the anil was thrice that of his son,eight years later the age of anil will be twice that of his son. find the present age of anil and his son ​

Answer 1

4 years Ago.

Let Son age=x years

Anil Age=3x years

Present Age .

Son=(x+4) years

Anil=(3x+4) years

8 years from Now.

Son=(x+4+8) years

Anil=(3x+4+8) years.

Now Anil is 2 twice the Age of his Son.

MEANS

2(x+4+8)=3x+4+8

2(x+12)=3x+12

2x+24=3x+12

2x-3x=12-24

$\cancel-x=\cancel-12$

Present Age of.

Son=x+8=12+4=16 years

Anil=3x+4=3×12+4=40 years

$\boxed{\mathbf{\huge{Son=16\:years}}}$

$\boxed{\mathbf{\huge{Anil=40\:years}}}$

Answer 2

Step-by-step explanation:

4 years Ago.

Let Son age=x years

Anil Age=3x years

Present Age .

Son=(x+4) years

Anil=(3x+4) years

8 years from Now.

Son=(x+4+8) years

Anil=(3x+4+8) years.

Now Anil is 2 twice the Age of his Son.

MEANS

2(x+4+8)=3x+4+8

2(x+12)=3x+12

2x+24=3x+12

2x-3x=12-24

\cancel-x=\cancel-12−x=−12

Present Age of.

Son=x+8=12+4=16 years

Anil=3x+4=3×12+4=40 years

\boxed{\mathbf{\huge{Son=16\:years}}}Son=16years

\boxed{\mathbf{\huge{Anil=40\:years}}}Anil=40years