Diagonal AC at parallelogram ABCD bisect angle A. Show that parallelogram ABCD is a rhombus
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ABCD is a parallelogram
and AC is a diagonal bisect angle A
angle CAD= BAC=ACD =ACD
IN TRIANGLE ABC and ADC
angle BAC=DAC
angle BCA=DCA
AC=AC
Therefore, triangle ABC congruance to triangle ADC.
AB=AD(C.P.C.T)
Hence, DC=AB=AD=BC.
All sides are equal in a palallelogram then it is a rhombus.
and AC is a diagonal bisect angle A
angle CAD= BAC=ACD =ACD
IN TRIANGLE ABC and ADC
angle BAC=DAC
angle BCA=DCA
AC=AC
Therefore, triangle ABC congruance to triangle ADC.
AB=AD(C.P.C.T)
Hence, DC=AB=AD=BC.
All sides are equal in a palallelogram then it is a rhombus.
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