Question

find the last digit of 2547^58

Answer 1

The last digit 2547^58 = 2547 ^ 4(14)+2

The last digit is 9 because it came 7²=49 in 49 the last digit is 9. so the last digit is 9.

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Answer 2

2547^58

step 1 :- given power 58 divide by 4
58 = 4×14 + 2
remainder = 2

step 2 :- now last digit take power 2
here last digit of 2547 is 7
so, (7)² = 49

hence, last digit of 2547^58 =9