Math, asked by akshayaashokan785, 12 hours ago

diagonal AC of a parallelogram ABCD bisect <A.show that ABCD is a rhombus.​

Answers

Answered by lachimolalajimin
9

Step-by-step explanation:

In △ABC,

⇒ ∠BAC=∠BCA

⇒ BC=AB [ Sides opposite to equal angles are equal ] --- ( 1 )

⇒ Also, AB=CD and AD=BC [ Opposite sides of parallelogram are equal ] ---- ( 2 )

From ( 1 ) and ( 2 ),

⇒ AB=BC=CD=DA

Hence, ABCD is a rhombus.

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