diagonal AC of a parallelogram ABCD bisect <A.show that ABCD is a rhombus.
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Step-by-step explanation:
In △ABC,
⇒ ∠BAC=∠BCA
⇒ BC=AB [ Sides opposite to equal angles are equal ] --- ( 1 )
⇒ Also, AB=CD and AD=BC [ Opposite sides of parallelogram are equal ] ---- ( 2 )
From ( 1 ) and ( 2 ),
⇒ AB=BC=CD=DA
Hence, ABCD is a rhombus.
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