Math, asked by ashishnidhi39, 13 hours ago

If (x + y) = 7 and xy = 2, find the value of x^3+y^3

Answers

Answered by AshwaniSingh19
0

Answer: 301

Step-by-step explanation:

x^{3} + y^{3}  = (x + y) (x^{2} -xy + y^{2}) = (x +  y) [(x^{2} + 2xy + y^{2}) - 3xy]

            = (x +  y) [ (x+y)^{2}  - 3xy]

            = (7) [(7)^2 - 3(2)] = 7 x (49 - 6) = 7x 43 = 301

Answered by bimlajajodia1
0

Answer:

(x^3 + y^3)=301

Step-by-step explanation:

(x+y)=7  &  xy=2

x^3 + y^3

(x+y)^3 = (x^3 + y^3) + 3xy (x+y)

(7)^3 = (x^3 + y^3) + 3X2 (7)

343 = (x^3 + y^3) + 6X7

343 = (x^3 + y^3) + 42

343-42 = (x^3 + y^3)

301 = (x^3 + y^3).

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