Question

Diagonal AC of a parallelogram ABCD bisects ∠A (see Fig.). Show that

(i) it bisects ∠C also,

(ii) ABCD is a rhombus.​

Answer 1

Step-by-step explanation:

x = 2 is a root of given equation substitute x = 2 in L.H.S.

L.H.S. = 3(2)2 – 2k × 2 + 2m = 0

12 – 4k + 2m = 0

4k – 2m = 12 …(i)

Similarly when x = 2 is root of given equation

Substitute x = 3 in L.H.S.

L.H.S. = 3(3)2 – 2k × 3 + 2m = 0

27 – 6k + 2m = 0

6k – 2m = 27 …(ii)

On solving equations (i) and (ii), we get

k = 15/2 and m = 9