Question

diagonal of a rectangle is 25 cm and length is 20 cm find the area of rectangle​

Answer 1

Answer:

By pythagoras theorem,

Breadth* breadth= 625-400=225

Breadth=15cm

Area of rectangle=Length*breadth=20*15=300cm square

Answer 2

$\huge\mathbb{\underline{SOLUTION:-}}$

$\sf\underline{\purple{\:\:\:\:Given\:\:\:\:}}$

$\sf\bullet diagonal \:of\: Rectangle=25cm\\ \\ \sf\bullet Length\:of\: Rectangle=20cm$

• Now by Pythagoras

$\boxed{\sf{Hypotenuse {}^{2}=base{}^{2}+perpendicular {}^{2}}}$

$\sf\implies (25){}^{2}=(20){}^{2}+b{}^{2}\\ \\ \sf\implies 625=400+b{}^{2}\\ \\ \sf\implies 625-400=b{}^{2}\\ \\ \sf\implies 225=b{}^{2}\\ \\ \sf\implies \sqrt{225}=b\\ \\ \sf\implies b=15cm$

Now the Area of rectangle

whose

• Length =20cm
• Breadth=15cm

$\boxed{\sf{Area\:of\: rectangle=length\times breadth}}$

$\sf\implies Area\:of\: rectangle=15\times 20\\ \\ \sf\implies Area=300cm{}^{2}$

$\boxed{\sf{\red{Area\:of\: rectangle=300cm{}^{2}}}}$