Question

Diagonal of a square is 20 cm find the length and perimeter of the square

Answer 1

Let side be x
Using Pythagoras theorem
diagonal =hypotenuse

x²+x²=20²
2x²=400
x²=200
x=10√2

Side is 10√2

Perimeter=4×10√2=>40√2cm

Answer 2

HII MATE HERE IS YOUR ANSWER
DIAGONAL OF SQUARE IS 20cm
Let the vertices of square is ABCD
diagonal of square is AC And BD and both diagonal are interesting on O
AO = 10 cm and BO = 10cm
By Pythagoras theorem
AO² + BO ²= AB ²
10² + 10² = AB²
100 +100 =AB²
AB²=200
AB = 10√2 cm
side of square is 10 √2 cm
perimeter of square = 4 × side = 4 × (10√2)
= 4× 10√2 = 40√2 cm
I HOPE IT WILL HELP YOU