diagonal of rhombus are in ratio of 5 :12 if its perimeter is 104 cm find the length of length of side and the diagonal
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5/12+x=104.
x=104×12/5.
x=1248÷5.
x=249.6
x=104×12/5.
x=1248÷5.
x=249.6
FarhanRock:
wrong solution
Answered by
3
Answer:
Step-by-step explanation:
Let ABCD be a rhombus with mid point as O.
AO = 2x
BO = 5x
AB is the hypotenuse.
AB= Root over of (12x)*2 +(5x)*2
=13x
Perimeter=104 cm*2
13x ×4=104
x=2
Thus, side=13x=26 cm
Diagonals are 24 cm and 10 cm
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