Question

Diagonals AC and BD of a cyclic quadrilateral ABCD intersect at right angles at E as shown in figure.A line drawn through E and perpendicular to AB meets at M and CD meets at F. prove that F is the mid point of CD.

Answer 1

here abcd is a rectangle
ab=cd horizontally
ad=bc vertically
we know that they meet at midpoint e join em and ef
there fore f is the midpoint of cd