Question

. Diagonals AC and BD of a quadrilateral
ABCD intersect at 0 in such a way that
ar (AOD) = ar (BOC). Prove that ABCD is a
trapezium.​

Answer 1

Answer:

ar(AOD) = ar(BOC)

1. Step-by-step explanation:

ar(AOD) = ar(BOC)

Add ar(ODC) both side

then

ar(ACD)=ar(BDC)

area of both tiangle are same

if the area of these triangles are equal

so they between same parallel line and same base

soAB parallel CD

Hence ABCD is a trapizum