Question

Diagonals AC and BD of a trapezium ABCD with AB||DC intersect each other at O. prove that ar(triangle AOD)=ar(triangle BOC).​

Answer 1

Step-by-step explanation:

here cd|| ab

angle dca=angle cab

angle cdb=angle dba

and angle doa= angle coa

so,

by aaa similarity we have rights to say that...

triangle Doa is congurant to angle cob...

hence, af triangle doa is equal to tangle cob....