The focal length of a convex mirror is 14 m, the distance of the object from the mirror is 8 m, the length of the object is 3 m, find the magnificent of the image and the length of the image.
No violation please
Answers
Yes
Refer the attachment.
Mark As Brainliest!
Answer:
The focal length of the mirror(f) = 14 m
The distance of the object (u) = 8 m
The length of the object (o) = 3 m
Let, the distance of the formed image be, 'v'
The length of the formed image be, 'i'
The magnificent of the image be, 'm'
Now let's come to the calculations_
We know that,
1/focal length = (1/distance of the object) + (1/distance of the formed image)
⇒ 1/f = (1/u) + (1/v)
⇒ 1/14 = (1/8) + (1/v)
⇒ (1/14)-(1/8) = 1/v
⇒ 1/v = (1/14)-(1/8)
⇒ 1/v = (4-7)/56 [∵ The L.C.M. of 14 and 8 is 56]
⇒ 1/v = -3/56
⇒ v = -56/3
⇒ v = -18.66 m
So, the image will form at a distance of_
(-18.66+8)
= -10.66 m beyond the centre of curvature.
Magnificent of the image(m) = - v/u
= - (-18.66/8)
= 18.66/8
= 2.3325
= 2.333
So, the magnificent of the image is 2.333
We know that,
m = i/o
⇒ 2.333 = i/3
⇒ 2.333×3 = i
⇒ i =6. 999
⇒ i = 7 m
So, the length of the formed image is 7 m
Explanation: