diagonals ACand BDof a quadrilateral ABCD intersect O in such a way that ar(AOD) =ar(BOC).proove thatABCD is a trapezium.
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you just add the ar(AOB) on both sides to get ar(ABD) = ar(ACB).
then by theorem
triangles on the same base and having equal area lie between same parallels. thus, CD is parallel to AB.
Hence, ABCD is a trapezium
then by theorem
triangles on the same base and having equal area lie between same parallels. thus, CD is parallel to AB.
Hence, ABCD is a trapezium
danishjoshi111:
nice
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