Question

Diagonals of a parallelogram ABCD intersect at O. If ∠BOC = 90° and ∠BDC = 50°, then ∠OAD is:

Answer 1

Given

∠BOC = 90°

∠ BDC = 50°

Step-by-step explanation:

Calculation

∠BOC + ∠COD = 180° (Linear Pair)

⇒ ∠COD = 180° - ∠BOC

⇒ ∠COD = 180° - 90°

⇒ ∠COD = 90°

∠COD + ∠ODC + ∠OCD = 180° (∠ Sum Property)

⇒ ∠OCD = 180° - 90° - 50°

⇒ ∠OCD = 40°

AB parallel CD

⇒ ∠OCD = ∠OAB = 40° (Alternate Interior ∠s)

∴ ∠OAB is 40°.

Please mark as brilliant answer

Answer 2

Step-by-step explanation:

please mark me brainly answer