Question

Diagonals of a rectangle ABCD intersect at 0.If Angel AOB=70°then find angel DCO

Answer 1

Answer:

Angle AOB = angle DOC = 70°

In ∆ DOC,

Angle DCO = angle CDO

and

Angle DCO + angle CDO + angle DOC = 180°

➠2 Angle DCO = 180°-70°

➠2 Angle DCO= 110°

➠Angle DCO = 55°

Hope it will help you.....

❤️Happy independence day ❤️