Question

Diagonals of a rhombus are 20 cm and 21 cm respectively, then find the side of rhombus and its perimeter.

Answer 1

We know that in a rhombus the diagonals bisect each other at 90


so let AC=20 AND BD=21 CM
AD=10 AND BO=10.5 CM
AB^2=AD^2+OB^2
=10^2+10.5^2
=100+110.25
=210.25
AB=14.5 IS THE SIDE OF THE RHOMBUS
PRIMETER=4S
=4(14.5)
=58 CM

Hope its help!!

Answer 2

Answer:

Side:14.5 perimeter:58

Step-by-step explanation:

We know that in a rhombus the diagonals bisect each other at 90

so let AC=20 AND BD=21 CM

AD=10 AND BO=10.5 CM

AB^2=AD^2+OB^2

=10^2+10.5^2

=100+110.25

=210.25

AB=14.5 IS THE SIDE OF THE RHOMBUS

PRIMETER=4S

=4(14.5)

=58 CM