In a rhombus PQRS if PQ = 7.5 then find QR. If ∠QPS = 75° then find the measure of ∠PQR and ∠SRQ.
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= 75We know that rhombus is a parallelogram with a pair of adjacent sides equal.
Here , PQRS is a rhombus.
Hence, adjacent sides PQ and QR are equal.
So,PQ =QR = 7.5 cm.
Now,
draw diagonal PR
we have, PQ=QR and ∠QPS = 75º
triangle PQR is isosceles
∠QPS = 75°
So, ∠SRQ = 75° (opposite angles of a rhombus are equal in measure)
∠PQR=(180-75-75)/2= 15° {Adjacent sides (ones next to each other) of a rhombus are supplementary. This means that their measures add up to 180 degrees.}
Here , PQRS is a rhombus.
Hence, adjacent sides PQ and QR are equal.
So,PQ =QR = 7.5 cm.
Now,
draw diagonal PR
we have, PQ=QR and ∠QPS = 75º
triangle PQR is isosceles
∠QPS = 75°
So, ∠SRQ = 75° (opposite angles of a rhombus are equal in measure)
∠PQR=(180-75-75)/2= 15° {Adjacent sides (ones next to each other) of a rhombus are supplementary. This means that their measures add up to 180 degrees.}
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