Math, asked by abc7285, 11 months ago

diagonals of a rhombus are 20 cm and 21 CM respectively then find the side of rhombus and its perimeter

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Answered by Anonymous

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Answered by Anonymous

Step-by-step explanation:

AnswEr:-

Perimeter of Rhombus = 58 cm.

Side of Rhombus = 14.5 cm

Step by Step Explanation:-

We know that Diagonals of the rhombus bisect each other at 90°.

$\rule{150}3$

By using Pythagoras theorem:-

$\longrightarrow\sf\; Side^2 = 10^2 + 10.5^2$

$\longrightarrow\sf\; Side^2 = 100 + 100.25$

$\longrightarrow\sf\; Side^2 = 210.25$

$\longrightarrow\large\boxed{\sf{\pink{ Side = 14.5}}}$

Hence, The side of the Rhombus is 14.5 cm.

$\rule{150}3$

Formula of Perimeter of Rhombus:-

$\longrightarrow\large\boxed{\sf{\red{ 4\times\; Side}}}$

$\longrightarrow\sf\; 4 \times \; 14.5$

$\longrightarrow\sf\; 58 cm$

So, The perimeter of Rhombus is 58cm.

$\rule{150}3$

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