Diagonals of the rhombus is thrice the other, sum of diagonals is 24cm and find the area of rhombus
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Given,
Diagonal of a rhombus is thrice the other.
let the two diagonals be x and 3x
sum of the two diagonals = 24cm
According to the problem,
x + 3x = 24cm
4x = 24cm
x = 24/4
x = 6
Then the other Diagonal = 3x = 3(6) = 18
Area of rhombus = d1d2 / 2
= 18 × 6 / 2
= 108/2
= 54 cm
Therefore, the area of rhombus is 54 cm.
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