diagram of the adjacent picture frame has outer dimensions are28*24and inner dimensions 20*16find the area of the shaded part of the frame
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Answered by
9
Area of shaded part of the frame = area of outer dimensioms - area of inner dimensions
= (28×24)-(20×16)
=672-320
=352 unit sq.
= (28×24)-(20×16)
=672-320
=352 unit sq.
rajnish6767:
wrong
Answered by
20
In Figure (I) and (II) are similar in
dimensions & also figures (III) and (IV) are similar in dimensions.
Width is 28- 24= 4 cm
Width is same of each section.
Width is height of all the trapezium.
Area of figure (I) = Area of
trapezium
= ½(sum of parallel sides) ( height)
= ½ (28+20)(4)
= ½( 48)(4)
= 48×2
= 96 cm²
Area of figure (II) = 96 cm²
Area of figure (I) = Area of figure (II) =
96 cm²
Area
of figure (III)
= Area of trapezium = ½(sum of
parallel sides) ( height)
= ½(24+16)(4)
= ½(40)(4)
= 40× 2
= 80 cm²
Area of figure (IV) = 80 cm²
Area of figure (III) = Area of figure (IV)
= 80 cm²
=========================================================
Hope this will help you.
dimensions & also figures (III) and (IV) are similar in dimensions.
Width is 28- 24= 4 cm
Width is same of each section.
Width is height of all the trapezium.
Area of figure (I) = Area of
trapezium
= ½(sum of parallel sides) ( height)
= ½ (28+20)(4)
= ½( 48)(4)
= 48×2
= 96 cm²
Area of figure (II) = 96 cm²
Area of figure (I) = Area of figure (II) =
96 cm²
Area
of figure (III)
= Area of trapezium = ½(sum of
parallel sides) ( height)
= ½(24+16)(4)
= ½(40)(4)
= 40× 2
= 80 cm²
Area of figure (IV) = 80 cm²
Area of figure (III) = Area of figure (IV)
= 80 cm²
=========================================================
Hope this will help you.
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