Question

Diameter of a circle is 13 cm and length of a chord of the circle is 12 cm. Find the

distance of the chord from the centre.​

Answer 1

Answer:

Ans:- 2.5 cm

Step-by-step explanation:

Given:-

Diameter (AB) = 13cm,

r = 6.5 cm

Chord (CD) = 12 cm

Construction:-

Join OC and OM ⊥ to CB

To find :- OM =?

Now, ∠OMC is right-angle triangle,

So, (OC) ² = (OM) ² + (CM) ² (Pythagoras

theorem formula)

(OM) ² = (OC) ² - (CM) ²

(OM) ² = (6.5)² - (6)²

(OM) ² = 42.25 - 36

(OM) ² = 6.25

(OM) = 2.5 cm

The distance between Chord and centre is 2.5 cm