Question

Diameter of a circle is 26 cm and the length of chord of a circle is 24 cm. find the distance of the chord from the centre.

Answer 1

aloha user!!
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we know a radius makes 90° angle on any chord and bisects it.
so,
radii=> 26/ 2 => 13 cm ( H )
base=> 24/ 2  => 12 cm ( B )
p= ?

H² = B² + P²
13² = 12² + P²
169 = 144 + P²
P²= 169 - 144
P² = 25
P= √ 25
P= 5cm 

The distance of chord from the centre is 5cm.
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hope it helps :^)

Answer 2

According to the ques the figure would be like so as attached.

Then OA = OB ⇒ 13 cm ;  AM = BM ⇒ 12 cm 
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Using Pythagoras theorem,

 OA² = OM² + AM²

(13)² = OM² + (12)²

 OM² = 169 - 144

  OM = √25 ⇒ 5 cm.
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Hence the distance from centre to the chord is 5 cm.
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