Diameter of a circle is 30cm if the leanth of a chord is 20cm . Find the distance of the chord from the centre
Answers
(Square of half of diameter) - square of half of chord
15^2 - 10^2 = ✓125
Or ✓5×5×5 = 5√5 ans
Answer:
Given : A circle of 30 cm diameter has a 24 cm chord.
To find : What is the distance of the chord from the center ?
Solution :
Diameter of circle = 30 cm
Radius of circle = 15 cm
Chord length = 24 cm
Using theorem perpendicular from the center bisect the chord the chord is bisected at 90 degree.
So the two parts of line is 12 cm each.
Applying Pythagoras theorem,
\text{Radius}^2=\text{One side of chord}^2+\text{Distance}^2Radius
2
=One side of chord
2
+Distance
2
15^2 = 12^2 + \text{Distance}^215
2
=12
2
+Distance
2
225 = 144 + \text{Distance}^2225=144+Distance
2
\text{Distance}^2=225-144Distance
2
=225−144
\text{Distance}^2=81Distance
2
=81
\text{Distance}=\sqrt{81}Distance=
81
\text{Distance}=9Distance=9
Therefore, the distance of the chord from the center is 9 cm.
#Learn more
Diameter of a circle is 26 CM. and length of a chord of the circle is 24 CM. Find the distance of the chord from the center.