Diameter of cylinder A is 7 cm, and the height is 14 cm. Diameter of cylinder B is 14 cm and height is 7 cm. Without doing any calculations
can suggest whose volume is greater? Verify it by finding the
me of both the cylinders. Check whether the cylinder with greater volume also has greater surface area?
Answers
Answer:
the cylinder of greater capacity has more surface area.
Radius(r) = CM, hieght (h) =14cm
.•. volume of cylinder A:- A=πr2h
= 22/7 ×(7/2)^2 ×14cm^3
=22/7×7/2×7/2×14cm^3
=11×7×7cm^3 =539cm^3
Volume of cylinder B
Radius(a) = 14/2 =7cm hieght (h) =7cm
.•. volume of cylinder B =π2^2h
= 22/7×(7)^2×7cm=22/7 ×7×7×7cm^3
=22×7×7=1078cm^3
thus, cylinder B has greater volume
Now,
Surface area of cylinder A=2×π×(r+h)
=2×22/7×7/2×[7/2+14 ]cm^2
= 22×35/2 cm^2=385cm^2
surface area of cylinder B =2πrh(r+h)
=2×22/7×7×[7+7]cm^2
=2 ×22 ×[14]cm^2=616cm^2
(hence verified)
thus, the cylinder of greater capacity has (more) surface area.
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volumeofcylinderA:−
Radius(r) = \frac{7}{2}27 CM, hieght (h) =14cm
.•. volume of cylinder A:- A=πr2h
= 22/7 ×(7/2)^2 ×14cm^3
=22/7×7/2×7/2×14cm^3
=11×7×7cm^3 =539cm^3
----------------------------------------------------------------------
Volume of cylinder B
Radius(a) = 14/2 =7cm hieght (h) =7cm
.•. volume of cylinder B =π2^2h
= 22/7×(7)^2×7cm=22/7 ×7×7×7cm^3
=22×7×7=1078cm^3
thus, cylinder B has greater volume
Now,
surface area of cylinder B =2πrh(r+h)
=2×22/7×7×[7+7]cm^2
=2 ×22 ×[14]cm^2=616cm^2
(hence verified)
thus, the cylinder of greater capacity has (more) surface area.