Diameter of the circular garden is 42 m. There is a 3.5 m wide road around the garden. Find the area of the road
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Solution :
Diameter of the Circular Garden = d
d = 42 m
Radius ( r )= OB = d/2 = 42/2 = 21 m
width of the around the Garden (w)=3.5m
Radius of the larger circle ( R )
= OA
= r + w
R = 21 + 3.5 = 24.5 m
Area of the Road ( A ) = π( R+r )( R-r )
A = ( 22/7 ) ( 24.5 + 21 )( 24.5 - 21 )
A = ( 22/7 ) × 45.5 × 3.5
A = 22 × 45.5 × 0.5
A = 500.5 m²
Therefore ,
Area of the Road = A = 500.5 m²
••••
Diameter of the Circular Garden = d
d = 42 m
Radius ( r )= OB = d/2 = 42/2 = 21 m
width of the around the Garden (w)=3.5m
Radius of the larger circle ( R )
= OA
= r + w
R = 21 + 3.5 = 24.5 m
Area of the Road ( A ) = π( R+r )( R-r )
A = ( 22/7 ) ( 24.5 + 21 )( 24.5 - 21 )
A = ( 22/7 ) × 45.5 × 3.5
A = 22 × 45.5 × 0.5
A = 500.5 m²
Therefore ,
Area of the Road = A = 500.5 m²
••••
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500.50 sq m square yes or no
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