In ABCD, l(AB) = 13 cm, l(DC) = 9 cm, l(AD) = 8 cm, find the area of ABCD.
mysticd:
plz , check the question again.
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Answered by
41
is it complete question ?
I think you should write ----> in trapezium ABCD, l(AB) = 13cm , l(DC) = 9 cm , l(AD) = 8 cm
then find area of ABCD ?
solution :- length of AB = 13cm
length of DC = 9 cm
length of AD = 8 cm
now use formula ,
area of trapezium ABCD = 1/2 { length of AB + length of DC} × length of AD
= 1/2 { 13cm + 9 cm} × 8 cm
= 22 cm × 4cm = 88 cm²
hence , area of trapezium ABCD = 88cm²
I think you should write ----> in trapezium ABCD, l(AB) = 13cm , l(DC) = 9 cm , l(AD) = 8 cm
then find area of ABCD ?
solution :- length of AB = 13cm
length of DC = 9 cm
length of AD = 8 cm
now use formula ,
area of trapezium ABCD = 1/2 { length of AB + length of DC} × length of AD
= 1/2 { 13cm + 9 cm} × 8 cm
= 22 cm × 4cm = 88 cm²
hence , area of trapezium ABCD = 88cm²
Answered by
0
Step-by-step explanation:
Draw perpendicular from c to line AB. Name the point E.
CE = AD = 8 cm
EB =
Area of rectangle AECD =
Area of Triangle BEC =
Area of ☐ ABCD = Area of AECD + Area of triangle BEC = 72 + 16 = 88 cm2
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