Question

Diamond has a refractive index of 2.42 .The speed of light in a vacuum is 300000km/s.calculate critical angle for diamond

Answer 1

Dear friend,

◆ Answer -

θ = 24.41°

● Explaination -

# Critical angle -

The angle at which the incident ray after refraction grazes is called the critical angle.

# Given -

μ = 2.42

c = 3×10^8 m/s

# Solution -

Critical angle is calculated by formula -

θ = arcsin(1/μ)

θ = arcsin(1/2.42)

θ = arcsin(0.4132)

θ = 24.41°

Therefore, critical angle for diamond is 24.41°.

Thanks for asking..

Answer 2

Explaination:-

The angle at which the incident ray after refraction grazes is called the critical angle.

Given:-

μ = 2.42

c = 3×10^8 m/s

Solution:-

Critical angle is calculated by formula -

θ = arcsin(1/μ)

θ = arcsin(1/2.42)

θ = arcsin(0.4132)

θ = 24.41°

Therefore, critical angle for diamond is 24.41°.