dice is rolling three times probability sum of number is prime less than 10
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A = { getting prime number less than 10 }
A = { (1,1,1)(1,1,3)(1,1,5)(1,2,2)(1,2,4)(1,3,1)(1,3,3)(1,4,2)(1,5,1)(2,1,2)(2,1,4)(2,2,1)(2,2,3)(2,3,2)(2,4,1)(3,1,1)(3,1,3)(3,2,2)(3,3,1)(4,1,2)(4,2,1)(5,1,1) }
n(A) = 22 ; n(S) = 216
p(A) = n(A)/n(S) = 22/216 (or) 11/108
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A = { (1,1,1)(1,1,3)(1,1,5)(1,2,2)(1,2,4)(1,3,1)(1,3,3)(1,4,2)(1,5,1)(2,1,2)(2,1,4)(2,2,1)(2,2,3)(2,3,2)(2,4,1)(3,1,1)(3,1,3)(3,2,2)(3,3,1)(4,1,2)(4,2,1)(5,1,1) }
n(A) = 22 ; n(S) = 216
p(A) = n(A)/n(S) = 22/216 (or) 11/108
HOPE IT HELPS YOU AND
MARK ME AS BRAINLIEST
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