dice is thrown once find the probability of not getting a factor of 36
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2
The total outcomes of dice are 6 {1,2,3,4,5,6}
The factor of 36 are 1,2,3,4,6
except 5 all are factors of 36
therefore not a factor of 36 = 5 i.e {1}
So P(Not getting a factor of 36) = 1/6
Answered by
12
the factors of 36 give on dice=1,2,3,4,6
Hence 5 is not a factor of 36
probability =1/6
Hence 5 is not a factor of 36
probability =1/6
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