dice is thrown twice What is the probability at
(i) 5 will not come up either time
(ii) 5 will come up at least once
Answers
Answered by
0
Answer:
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Answered by
2
Step-by-step explanation:
I) n(a) = (5,1) (5,2)....(5,6)
(1, 5) (2, 5)......(6, 5)
n(s) = 36
p(a) = n(a) /n(s)
p(a) = 12/36
p(a) = 1/3
ii) n(a) = (5, 1) (5, 2).....(5, 6)
(1, 5) (2, 5).....(6, 5)
p(a) = n(a) /n(s)
=12/36
=1/3
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