Math, asked by amankhan4128, 1 month ago

did a cubic polynomial whose zeros are 3 ,5 and -2​

Answers

Answered by n7428950879
1

Answer:

sum of zeroes = coefficient of x2coefficient of x3.

product of the zeroes = consent termcoefficient of x3.

sum of product of zeroes = coefficient of xcoefficient of x3.

sum of zeroes = coefficient of x2coefficient of x3.

product of the zeroes = consent termcoefficient of x3.

Answered by xSoyaibImtiazAhmedx
1

Answer:

Let the cubic polynomial be ax³ + bx² + cx + d

Given zeros →

 \alpha  = 3

 \beta  = 5

 \gamma  =  - 2

Now,

 \alpha  +  \beta  +  \gamma  =  \frac{ - b}{a}

 \implies \: 3 + 5 + ( - 2) =  \frac{ - b}{a}

 \implies \: 6 =  \frac{ - b}{a}

 \implies \:  \frac{b}{a}  =  \frac{ - 6}{1}

b = -6 and. a = 1

 \alpha  \beta  +  \beta  \gamma  +  \gamma  \alpha  =  \frac{c}{a}

 \implies \: 3 \times 5 + 5 \times ( - 2) + ( - 2) \times 3 =  \frac{c}{a}

 \implies \: 15 - 10 - 6 =  \frac{c}{a}

 \implies \: 15 - 16 =  \frac{c}{a}

 \implies \:  - 1 =  \frac{c}{a}

 \implies \:  - 1 =  \frac{c}{1}

 \implies  \bold{\: c \:  =  - 1}

c = -1

 \alpha  \beta  \gamma  =  \frac{ - d}{a}

 \implies \: 3 \times 5 \times ( - 2) =  \frac{ - d}{1}

 \implies \:  - 30 =  - d

 \implies \:  \bold{d \:  = 30}

d = 30

So, the cubic polynomial

→ x³ -6 x² - x + 1

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