Question

Diego is flying his kite one afternoon and notices that he has let out the entire 120ft of string. The angle his string makes with the ground is 52º. How high is the kite at this time?

Answer 1

Answer:

94.6ft

Step-by-step explanation:

sine(52°) = x/120

multiply both sides by 120

120 sine(52°) = x

put it in a calculator

x = 94.56129043

round to nearest tenth

x = 94.6ft

Answer 2

The height of the kite from the ground is 94.56 ft

Step-by-step explanation:

Given: Length of the string is 120 ft.

The angle of the string is 52 degree

To find: The height of the kite from the ground

Solution

We have AB is the length of the string

θ= 52 degree

Right angled triangle:

• 90 degrees is the right angle. The three sides of a right-angled triangle are known as the perpendicular, base (adjacent), and hypotenuse (Opposite).
• The side of the triangle that makes a right angle with the base is called perpendicular.

In a triangle ABC,

$sin 52^{0} = \frac{BC}{AB}$

BC = AB $sin 52^{0}$

Length of the string AB is 120

AB = 120

Sub AB =120 in the formula

BC = AB $sin 52^{0}$

BC = 120 $sin 52^{0}$

$sin 52^{0} = 0.788$

BC = 120 × 0.788

BC = 94.56

Height of the kite is 94.56.

Final answer:

The height of the kite from the ground is 94.56 ft

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