Math, asked by choudharyhritika143, 10 months ago

If secA+tanA=pand secA-tanA=q,then the value of pq is

Answers

Answered by luckyshukla55

0

Answer:

pq=1

Step-by-step explanation:

(secA+tanA)(secA-tanA)=pq , sec2A-tan2A=pq , (sec2A-tan2A=1) , so pq=1

Answered by asdfmeena2022

0

(secA-tanA)(secA+tanA)
1

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